A wave whose cycles have period .000056 second travels at velocity 3339 meters/second. What is its wavelength?
If the wave is traveling at 3339 meters/second, then in .000056 second the wave will travel through a peak-to-peak cycle. During .000056 second the wave travels ( 3339 meters/second) ( .000056 second) = .187 meters, which must therefore be the peak-to-peak distance. The wavelength is therefore .187 meters.
If it takes a cycle of length `lambda a total time T to pass, the velocity of the wave must be